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Mathematics 20 Online
OpenStudy (anonymous):

Abelardo wants to create several different 7-character screen names. He wants to use arrangements of the first 3 letters of his first name (abe), followed by arrangements of 4 digits in 1984, the year of his birth. How many different screen names can he create in this way? A) 72 B) 144 C) 288 D)576

OpenStudy (anonymous):

please help(:

OpenStudy (anonymous):

ummm??? sorry Im confused

OpenStudy (anonymous):

please help!(:

OpenStudy (anonymous):

Letters Arranged in 3! = 6 ways

OpenStudy (anonymous):

numbers Arranged in 4! = 24 ways

OpenStudy (anonymous):

6 x 24 = 144 my bad !

OpenStudy (anonymous):

where does the seven character screen names come into place?

OpenStudy (anonymous):

it doesnt

OpenStudy (anonymous):

wait so how did we get to the answer of 72?

OpenStudy (anonymous):

the first one was a typo

OpenStudy (anonymous):

so its 144?

OpenStudy (anonymous):

uhhh, yeah

OpenStudy (anonymous):

this is still confusing

OpenStudy (anonymous):

look, maybe you should consult with someone else, Since you obviously do not like my answer

OpenStudy (anonymous):

the number of permutations of n different objects taken r at a time and is denoted by nPn Note that when r = n, nPn= n!

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