Question

Solve and check...
2x^2+2x=4

Answer 1

are you finding the solutions?

Answer 2

Are you tying to solve for x??

Answer 3

i mean x=-2 and x=1

Answer 4

@Jasmine2012 That's wrong

Answer 5

Solve for x...

Answer 6

no its right

Answer 7

What's not right??

Answer 8

Working with functions....the answers should be a pair of numbers

Answer 9

yes ther are x=-2,1

Answer 10

just not sure how to solve the equation

Answer 11

Well I would do it this way
First bring the 4 to the other side of the equation to make a quadratic
\[2x^{2}+2x-4=0\]
Because the 4 moved to the other side of the equal line it changed signs now solve.
What two numbers when multiplied will give you -4 and when added will give you 2??

Answer 12

2x^2+2x=4
divide both sides by 2, we get
x^2 + x = 2
or
x^2 + x - 2 = 0
this can be factorised as follows
x^2 + 2x - x - 2 = 0
x(x+2) -1(x+2) = 0
(x+2)(x-1)=0
so
x= -2 or x= 1

Answer 13

thats what i said along time ago

Answer 14

That's wrong

Answer 15

@Harkirat that's wrong

Answer 16

2 times -2 = -4 but when added equals 0

Answer 17

@BABYShawol184
point out what is wrong......

Answer 18

i got the same thing as Harkirat x=-2 and x=1

Answer 19

When -2 is put back into the equation the left side and right side don't equal

Answer 20

NEVERMIND!!! My mistake

Answer 21

yeah i thought so...

Answer 22

So sorry made a huge mistake! @Harkirat is right :) Sorry

Answer 23

2x^2+2x=4
substitute x = -2

LHS = 2*(-2)^2 + 2(-2) = (2*4)-4 = 8-4=4=RHS

Answer 24

@BABYShawol184
No problem......we all goof up sometimes....
MATHS.....Memory At Times Has (to) Slip...

Answer 25

Thank you all!!

Answer 26

no problem

Answer 27

@Harkirat Haha :) I'll remember that :)

Answer 28

yes it was pretty easy but if you need anything else im here :)