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Calculus1 8 Online
OpenStudy (anonymous):

if f(x)=x*e^(-2*x^2), then f'(x)=e^(-2*x^2), right?

OpenStudy (anonymous):

No, I just made the same mistake as you a minute ago though lol So, the rule for \[f'(x) = e ^{g(x)} \] is \[g'(x)*e ^{g(x)}\]

OpenStudy (anonymous):

So you'd have the derivative of the function e is being raised to times the original function. And don't forget the product rule since you have an x in there. See if you can do it from there =)

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