What is the sum of the infinite geometric series 1/2 +1/4 + 1/8 + 1/16 +... ?
well, you can see the pattern, right?
a1=1/a0, a2=1/2*a1, a3=1/2*a2, etc.
|dw:1365365965098:dw|
converges to 1
there is an exact formula but I don't remember sorry...
\[\sum_{n=0}^{\infty}\frac{ 1 }{ 2n }\]
I think that's about right.
it's geometric.
the formula is Sn=(t1(1-r^n))/1-r
Any infinite geometric series has an infinite sum of S = a/(1-r) where a = first term r = common ratio and |r| < 1 If |r| > 1, then the series doesn't converge
the formula for the sum uses a=first term r=ration you're multiplying by and the formula is a/(1-r) if I remember correctly
whats the n amount? in the formula i listed above?
the formula you listed sparky16 is only used for partial sums
oh is it this formula: S=t1/1-r and r has to be less than 1
more like |r|<1, but yes
so after plugging that in, I got 1. Is that correct?
yes S = a/(1-r) S = (1/2)/(1-1/2) S = (1/2)/(1/2) S = 1
thank you so much(:
np
Join our real-time social learning platform and learn together with your friends!