David kicks a soccer ball off the ground and in the air with an initial velocity of 35 feet per second. Using the formula H(t) = −16t2 + vt + s, what is the maximum height the soccer ball reaches? (4 points) 17.9 feet 18.2 feet 18.7 feet 19.1 feet
Test? :P
hah no, worksheet
H(t)- height reached at time t right? You will have to differentiate it wrt time to get the velocity at any time t.
Oh no...
wait, why no
hmm.. brb.
ok, cool
you know how to find the maxima of an equation right? suppose i give you an equation y= −16t2 + vt + s, find the value of t for which y is maximum. you'll be able to do it?
yeah, i can
No.. wrong again. wait. i didnt look at constant v.. What we have to first is. differentiate it wrt time. It would give us the velocity equation. we know v at t=0 is 35f/sec, find the constant v.
haha ok
IM A FLYING BOY
So after finding the constant v, plug it back in the equation H(t), differentiate it again, put it equal to zero, you'll get a value of t, the double derivative of the equation would be <0 , so that obv would be the maximum value. Put that time back into the equation of h(t) and find the maximum height. But... what about constant s? :O
ohh, ok! i have the answer. thanks! @yrelhan4
How did you do it? Find the time period of the whole trajectory and dividing it by 2? Does that work?
i got D. haha not hard
Alright.
How did you do it? :O
uhh, just used my brain
No i mean the method lol.
give up yrelhan shes smarter
ahah i just substituted the numbers into the equation and solved
Ha, of course she's smarter. I'll note this question down though and try to solve it.
like b=35 a=-16
Hmmm... It would take me time lol. I'm not as smart as you after all.
Its not D. :P
Think about it. Its easy though. A hint: s should be 0. why?
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