A certain culture of the bacterium Streptococcus A initially has 12 bacteria and is observed to double every 1.5 hours.
Estimate the number of bacteria after 26 hours.
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OpenStudy (anonymous):
Is there an equation?
OpenStudy (anonymous):
\[n(t)=12*2^{t/1.5}\]
OpenStudy (anonymous):
I know 26 goes in for t but idk how to do the rest. thats my problem
OpenStudy (anonymous):
Are you working with a text book? If you are what is the answer?
OpenStudy (anonymous):
no im not. its online.
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OpenStudy (anonymous):
Ok well when you put 26 into the equation it's in the exponent so we divide it by 1.5 so what do you get?
OpenStudy (anonymous):
\[17\frac{ 1 }{3 }\]
OpenStudy (anonymous):
\[n(26)=12*2^{17\frac{ 1 }{3 }}\] ?
OpenStudy (anonymous):
Good Now notice that the 12 and the 2 are separate so the exponent - the answer we just got- will only be applied to the 2. So now put 2 to the power of \[17\frac{ 1 }{ 3 }\]
OpenStudy (anonymous):
What do you get?
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OpenStudy (anonymous):
So... I got (165140.3719) now we multiply this by 12 to get our final answer which is 1981684.462 or (1.9 x 10^6)