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Mathematics 30 Online
OpenStudy (anonymous):

A certain culture of the bacterium Streptococcus A initially has 12 bacteria and is observed to double every 1.5 hours. Estimate the number of bacteria after 26 hours.

OpenStudy (anonymous):

Is there an equation?

OpenStudy (anonymous):

\[n(t)=12*2^{t/1.5}\]

OpenStudy (anonymous):

I know 26 goes in for t but idk how to do the rest. thats my problem

OpenStudy (anonymous):

Are you working with a text book? If you are what is the answer?

OpenStudy (anonymous):

no im not. its online.

OpenStudy (anonymous):

Ok well when you put 26 into the equation it's in the exponent so we divide it by 1.5 so what do you get?

OpenStudy (anonymous):

\[17\frac{ 1 }{3 }\]

OpenStudy (anonymous):

\[n(26)=12*2^{17\frac{ 1 }{3 }}\] ?

OpenStudy (anonymous):

Good Now notice that the 12 and the 2 are separate so the exponent - the answer we just got- will only be applied to the 2. So now put 2 to the power of \[17\frac{ 1 }{ 3 }\]

OpenStudy (anonymous):

What do you get?

OpenStudy (anonymous):

So... I got (165140.3719) now we multiply this by 12 to get our final answer which is 1981684.462 or (1.9 x 10^6)

OpenStudy (anonymous):

Hope this helped :)

OpenStudy (anonymous):

im loving you right now thank you :)

OpenStudy (anonymous):

so i didnt have to do anything with the n(26)?

OpenStudy (anonymous):

that was the part that messed me up

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