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find the lim....
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@mathstudent55
\[\sum_{i=1}^n i=\frac{n(n+1)}{2}\]
what is that @sirm3d
@electrokid could you please explain how to find the lim
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\[\sum_{n=1}^n\left(\frac{14i}{n}\cdot\frac{6}{n}\right)=\frac{84}{n^2}\sum_{n=1}^n i\]
the answer is not 84 you are confusing me. @sirm3d
i did not say 84 is the answer. i am showing partial solution
\[\frac{84}{n^2}\sum_{n=1}^n i=\frac{84}{n^2}\cdot\frac{n(n+1)}{2}\] now evaluate the lim at infinity of the right hand side of the equation
is tje answer 42?
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right. it's 42.
are you sure??? @sirm3d
yup.
thank u @sirm3d
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