Question

derivative of cosx/3+sinx

Answer 1

using quotient rule: dy/dx = [f(x)'g(x) - f(x)g'(x)]/ g(x)^2

so it is -sinx(3+sinx) - cosx(3+cosx) / (3+sinx)^2

and just simplify and your done

Answer 2

um for the derivative of cosx(3+sinx)= I got cosx(cosx)

Answer 3

my mistake sorry haha your right once you made that change, then just simplify and your done

Answer 4

for the answer I got -3sinx-1/(3+sinx)^2 is that right

Answer 5

its okay

Answer 6

hm.. your top is -sinx(3+sinx)-cosx^2 / (3+sinx)^2
so the top would be -3sinx - sinx^2 - cosx^2 / (3+sinx)^2

Answer 7

yes so I take the -(3sinx+sin^2 x+cos^2 x)

Answer 8

then sin^2 x + cos^2 x equal one

Answer 9

lol yea thats right

Answer 10

but do u understand how I got my answer cuz its a quiz question and I need to know if the answer I got is right? :(

Answer 11

everything you did is correct so far

Answer 12

my answer is -3sinx-1/ (3+sinx)^2

Answer 13

that should be fine

Answer 14

ok thanx :)

Answer 15

np glad to help