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integral x/(x^2-2xcos(a)+1) ?
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I assume that a is just any given constant is that correct?
So you're taking this integral with respect to the x differential, dx dimension.
a is a constant
For the denominator consider the following: \[x^2-2x \cos(a)+1=(x- \cos(a))^2 +1 - \cos(a)^2 =(x- \cos a)^2+ \sin^2 a\]
That should already simplify your integral by a good bit.
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From there I'd recommend to continue with an u-substitution. I think that's all.
u substitute for (x−cos(a))?
exactly that's what I would do, then you can express the numerator in terms of that too, will result in two easy integrals. Since a is any constant, du=dx
Did that help you to get the answer @atsitpfp ?
yes, thank you, i've got the right answer :)
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great, well done!
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