400 cm3 of mercury at 0 degrees Celcius will expand to what volume at 50 degrees Celcius?

Question

anonymous · Answer

403.6 cm^3

anonymous · Answer

How did you get that?  Please explain

anonymous · Answer

If the volume V0  of mercury is heated from t1 degree C to t2 degree C, then the volume v1 of mercury after  expansion  is given by:

v1 = v0(1+gamma(t2-t1)), where  gamma is the coefficient of volume expansion of mercury and is given to be 180*10^-6 /C. Substituting the given values,

v1= 400(1+180*10^-6*(50-0))

=403.6 cm^3.

anonymous · Answer

So your equation is $$V _{1} = V _{0} ( 1 + 180 \times 10^{-6}) (50 - 0)$$

anonymous · Answer

Correct

anonymous · Answer

So, if you go through and solve you should get $$403.6 cm^{2}$$

anonymous · Answer

I got it. Thank you very much!  Mind helping me with a few more questions?

anonymous · Answer

403.6cm^3*

anonymous · Answer

I'll answer if I can help. Don't forget to award me best response and close this question. ;P