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Mathematics 18 Online
OpenStudy (anonymous):

20.00 cm of total space is available. How long of a piece of brass at 20 degrees Celsius can be put there and still fit at 200 degrees Celsius? Brass has a linear expansion coefficient of 19X10^-6

OpenStudy (anonymous):

\[19.79 cm ^{3}\]

OpenStudy (anonymous):

Work please?

OpenStudy (anonymous):

Brass is 57 x 10^-6 m/m K volumetric expansion Original volume = 0.00002 m^3 Delta T = 180 degrees K So, if brass cools you get \[19.79cm ^{3}\]

OpenStudy (anonymous):

Why are you using volume? It is asking for length

OpenStudy (anonymous):

You need to go by volume at first because they don't give you length originally and the formula for volume is LxWxH you need L so you're going to need the volume to find the L.

OpenStudy (anonymous):

Do you understand now?

OpenStudy (anonymous):

Well, based off the equation I have, you don't need length \[L _{1} = L _{0} \beta \Delta T \]

OpenStudy (anonymous):

I mean, you don't need volume

OpenStudy (anonymous):

Can you just show me your equation please?

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