Question

Anyone want to help me please?:))

Answer 1

let the question be revealed

Answer 2

\[\frac{ 9x ^{2}-1 }{ 8x-4 }\div \frac{ 3x ^{2}+5x-2 }{ 2x ^{2}+1x-1 }\]

Answer 3

change the "division" to multiplication and flip the fraction after it

Answer 4

then factor out each of the polynomials

Answer 5

Oh so it's the keep change flip thing correct?

Answer 6

yep. lets see how you do it though.. to make sure

Answer 7

I'll try and get back to you:)

Answer 8

\[
\frac{(3x-1)(3x+1)}{4(2x-1)}\times\frac{2x^2+x-1}{3x^2+5x-2}
\]

Answer 9

Oh thanks that's nice of you:)

Answer 10

factorize the two trinomials on the right

Answer 11

Will do

Answer 12

\[\frac{ \left( x+1 \right)\left( 2x-1 \right) }{ \left( x+2 \right)\left( 3x-1 \right) }\]

Answer 13

@electrokid :)?

Answer 14

I think I got it
\[\frac{\left( 3x-1 \right) \left( 3x+1 \right) \left( x+1 \right)}{ 4\left( 5x+7 \right) }\]

Answer 15

check the cancellations again...

Answer 16

really:/

Answer 17

that (3x-1) wouldnt be there anu=ymore

Answer 18

and the denominator

Answer 19

I give up!! Thanks:)

Answer 20

what?
\[
\frac{\cancel{(3x-1)}(3x+1)}{4\cancel{(2x-1)}}\times\frac{ \left( x+1 \right)\cancel{\left( 2x-1 \right)} }{ \left( x+2 \right)\cancel{( 3x-1)} }
\]