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Write the linear combination of cosine and sine as a single cosine with a phase displacement: y=12cos(theta)+5sin(theta)
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I think i got it, but can you check my work? >.>
\[y=12\cos \theta+5\sin \theta \] b=12, c=5; \[A=\sqrt{144+25}\] \[A=13\] D=arctan(12/5) =tan^-1(12/5)+180*n where n belongs to the integers. Because both cosine and sine are positive, the quadrant the angle terminates in is QI. \[y=13\cos( \theta -67.38013505...*)\]
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