Question

solve g^x+2 = (1/27) ^x=12

Answer 1

Okay, so you first take (1/27)^x=12
Taking log on both sides, you have
xlog(1/27)=log(12)
That ix, -3xlog(3)=log(12)
*I trust you're aware how)
Which gives me, x= -[log(12)/3log(3)]

Answer 2

in g^x+2=12
I subtract both sides of equation by 2
so g^x=10
Again, log on both sides
xlog(g)=log(10)
thus log(g)=log(10)/x
here you substitute the value of x.

Answer 3

and that gives you log(g)= -3log(10)log(3)/log(12)

then you take the anti log on both sides.

Answer 4

I believe that solves your query.