the domain of 2/x+1 -3
is that (2/x)+1-3, or is that (2/x+1)-3?
(2/x+1) -3
k. so set it equal to 0. You get (2/x+1)-3=0, move three to the other side, and get (2/x+1)=3. Then cross multiply and you get 2=3(x+1). Foil it out. You get 2=3x+3. Solves for -1/3=x. Does that make sense?
yeah got it so the domain is -1/3
ooohhh. No its not. my bad ok so
(2/x+1)-3. Ok, what number can you NOT divide by in math?
-3
You CANT divide by 0 because it doesnt work. So set the denominator in 2/(x+1), which is x+1, equal to 0. So you get x+1=0. Move 1 to the other side and you get x=-1. So the domain of the function is from
its -1 ?
-infinity to -1, -1 to +infinity
Yes its -1
because the denominator in your question is x+1. 3 is not a part of it
and if you want that domain in range notation, its -infinity<-1<+infinity i believe
Does that make sense?
so the domain for (-3/x+4 )+2 is -2 ?
yes it does
if you have x+4 as your denominator, set that equal to zero. what do you get?
and no its not. The domain can be everything BUT what makes the domain 0. So if it cant be -1, domain is everything else from -infinity to +infinity
If you want, I can do a more in depth answer so I explain everything. Would you prefer that?
its actually x-4
Ok. So what is domain? Domain is values of x. Its easier to find everything that x CANT be. In the case of the equation you have, you are dividing by x. In math, you cant divide by 0, so you set x-4=0. Move that over, you have x=4, so the domain is everything BUT that, from -inifnity to 4, and from 4 to +infinity.
ok got it
Kk! Glad I could help! Sorry if I was a bit muddled at the beginning.
now the range (2-x-3 )-5
okay. well I assume that (-2-x-3)-5 is equal to y, so you have (-2-x-3)-5=y, so you can have y be anything from negative to positive infinity. can you see why?
2/x-3) -5 actually sorry
kk. what do YOU think it is?
-infinity 3 to + infinity 3
remove that last 3 and you have it correct
(1/x+1 ) -4 +infinity 1 to - infinity
i think?
-1 :)
-1 where?
because x+1=0, x=-1 if you rearrange
-1 in your domain
+infinity -1 to - infinity ?
yup
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