Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

help me with this question please. see the attachment..

OpenStudy (anonymous):

You are yet to attach the file.

OpenStudy (anonymous):

OpenStudy (anonymous):

@NeetziD, i posted the file

OpenStudy (anonymous):

Most easy way to see Taylors polynomial is in differentials: \(f(x_1+h,x_2+k,x_3+l)=f(x_1,x_2,x_3)+df+\frac{1}{2!}d^2f+...+\frac{1}{n!}d^nf+R_2\) where \(d^nf\) are the diferentials of f

OpenStudy (anonymous):

\(df=hf_{x_1} + kf_{x_2}+lf_{x_3}\) \(d^2f=h^2f_{x_1x_1}+hkf_{x_1x_2}+hlf_{x_1x_3}+hkf_{x_2x_1}+k^2f_{x_2x_2}+klf_{x_2x_3}+hlf_{x_3x_1}+klf_{x_3x_2}+l^2f_{x_3x_3}\)

OpenStudy (anonymous):

you are only asked for 2º order expantion, so you will need only this differentials. Now calculate the derivatives and substitute all that into the 1º equation that I posted with \(x_1=1,x_2=1,x_3=0\)

OpenStudy (anonymous):

@vamgadu

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!