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Can anyone please help and explain?
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Step by step:- Step one, subtract 8 brom both sides.
from*
\[-\sqrt[3]{4x} = 2\]
Now take cube on both sides.
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\[-\sqrt{4x} = 8\]
No. That's an error. See, that sign above 4 is, implies that it's the third root of 4x. Not (4x)^3/2 It's just -(4x)^1/3
So technically, what you get is -4x=8. You can find the value of x, now.
\[\sqrt[3]{a}\] is actually a^(1/3)
ok just a moment please
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so you cancel the cube when you take cube on both sides?
Yes. That's not cube, by the way, that's 1/3 rd exponential power.
Thankyou. so is x=-2?
Yes.
Thank you so much!!!
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Glad to help. =)
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