Question

Using the substitution u = 1+(x)^1/2 find:

Answer 1

\[\int\limits_{}^{}\frac{ 1 }{ 1+\sqrt{x} }dx\]

Answer 2

if u= 1+x^(1/2)
what is 'x' in terms of u ?

Answer 3

u = 1 + sqrt(x) ----> sqrt(x) = u - 1
du = 1/2sqrt(x) dx
2 sqrt(x) du = dx
2(u-1) du = dx

now, ur integral can be :