Question

http://static.k12.com/packages4/files/media/mathml_bda8343fe3cb34e3c1baeb47e8bbc88331b21958_1.gif

Answer 1

A.6/121
B.18/10
C.6/11
D.18/11

Answer 2

ur the only one whos helped me since 7:00 A.M

Answer 3

lol are you serious

Answer 4

yea

Answer 5

you shud write the numbers as squares
\[\frac{36}{121}=\frac{6^2}{11^2}\]

Answer 6

so cross multiply?

Answer 7

use
\[\frac{a^2}{b^2}=(\frac{a}{b})^2\]

Answer 8

this is not an equation so no cross multiplying

Answer 9

i thought i answered, but it guess it is not clear
the square root of 36 is 6, and the square root of 121 is 11

Answer 10

k

Answer 11

Or even,\[\sqrt{\dfrac{a}{b}} = \dfrac{\sqrt a}{\sqrt b}\]

Answer 12

and also
\[\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}\]

Answer 13

yes @satellite73

Answer 14

@satellite73 Coincidences.

Answer 15

making
\[\sqrt{\frac{36}{121}}=\frac{\sqrt{36}}{\sqrt{121}}\]
\[=\frac{6}{11}\]

Answer 16

so you where actually answered b4 by @satellite73 , @fosterthepeople5

Answer 17

@satellite73 Spoilers ahead.

Answer 18

yea @Jonask

Answer 19

\[\sqrt{.04}=\sqrt{\frac{4}{100}}=\frac{\sqrt{4}}{\sqrt{100}}=\frac{2}{10}=0.2\]

Answer 20

\[\sqrt{\frac{144}{49}}=\frac{12}{7}\] they get quicker as you go

Answer 21

yea