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Mathematics 24 Online
OpenStudy (anonymous):

Completely factor the polynomial 5x^3+40x^2+5x+40

OpenStudy (mertsj):

First factor out the common factor which is 5

OpenStudy (anonymous):

so would it be x^2+8x+x+8

OpenStudy (mertsj):

5(x^3+8x+x+8)

OpenStudy (anonymous):

when factoring 3x^9+6x^8-9x^7+6x^6 would you just divide it by 3?

OpenStudy (mertsj):

8x^2.

OpenStudy (mertsj):

Not done with the first one yet.

OpenStudy (mertsj):

The factors of 8 are possible rational roots so use synthetic division to find if there are any rational roots.

OpenStudy (anonymous):

oh okay 8x^2....?

OpenStudy (anonymous):

rational roots?

OpenStudy (mertsj):

You are supposed to factor. If you know the roots, you know the factors.

OpenStudy (anonymous):

okay so for 5(x^3+8x^2+8) would be (2x+4)(2x+4)

OpenStudy (anonymous):

That or it could be 4

OpenStudy (mertsj):

You are trying to factor x^3+8x^2+x+8

OpenStudy (mertsj):

If there are any rational zeros, they are factors of 8. What are the factors of 8?

OpenStudy (anonymous):

are the they ones we add or multiple to get 8?

OpenStudy (anonymous):

because if we are multiplying it would be 2*4 adding would be 4+4 or 6+2

OpenStudy (mertsj):

Factors of 8 are positive 1 and negative 1, positive 2 and negative 2, positive 4 and negative 4, positive 8 and negative 8

OpenStudy (mertsj):

Now use synthetic division to find out if any of those possibilities are actual roots.

OpenStudy (mertsj):

Does any of this sound familiar?

OpenStudy (anonymous):

some but never heard the term of synthetic division?

OpenStudy (mertsj):

What are you studying and what method did your teacher show you for factoring cubics?

OpenStudy (mertsj):

Oh...I bet you're supposed to factor by grouping.

OpenStudy (anonymous):

algebra 1, he hasn't shown us anything it's all been online. He isn't really much help.

OpenStudy (mertsj):

Group the first two terms and factor out 5x^2. Group the last two terms and factor out 5

OpenStudy (anonymous):

factoring out 5x^2 = 4x(x-1)

OpenStudy (mertsj):

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