Completely factor the polynomial 5x^3+40x^2+5x+40
First factor out the common factor which is 5
so would it be x^2+8x+x+8
5(x^3+8x+x+8)
when factoring 3x^9+6x^8-9x^7+6x^6 would you just divide it by 3?
8x^2.
Not done with the first one yet.
The factors of 8 are possible rational roots so use synthetic division to find if there are any rational roots.
oh okay 8x^2....?
rational roots?
You are supposed to factor. If you know the roots, you know the factors.
okay so for 5(x^3+8x^2+8) would be (2x+4)(2x+4)
That or it could be 4
You are trying to factor x^3+8x^2+x+8
If there are any rational zeros, they are factors of 8. What are the factors of 8?
are the they ones we add or multiple to get 8?
because if we are multiplying it would be 2*4 adding would be 4+4 or 6+2
Factors of 8 are positive 1 and negative 1, positive 2 and negative 2, positive 4 and negative 4, positive 8 and negative 8
Now use synthetic division to find out if any of those possibilities are actual roots.
Does any of this sound familiar?
some but never heard the term of synthetic division?
What are you studying and what method did your teacher show you for factoring cubics?
Oh...I bet you're supposed to factor by grouping.
algebra 1, he hasn't shown us anything it's all been online. He isn't really much help.
Group the first two terms and factor out 5x^2. Group the last two terms and factor out 5
factoring out 5x^2 = 4x(x-1)
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