ln√(x+4) - 2 = -1, solve for x
Do you think you know what the answer might be or how to get it?
I think I have an idea and have an answer, but I don't know if it is correct.
first, add by 2 to both sides, will giving us ln√(x+4) - 2 = -1 ln√(x+4) - 2 + 2 = -1 + 2 ln√(x+4) = 1
Have that.
And what is your idea?
Then I divided both sides by "e" canceling out the ln and getting me .36788 on the other side.
Wait why are you dividing by e?
This is new to me. I thought that the ln is equal to e - .271828 Am I wrong?
then setting 1 to ln e now, u have an equation ln√(x+4) = 1 ln√(x+4) = ln e cancel out "ln" √(x+4) = e solve for x
Oh, thank you. That makes more sense. Got it.
you're welcome
3.3891 should be my answer for x. Correct?
from √(x+4) = e squares both sides : x+4 = e^2 subtract by -4 x+4-4 = e^2 - 4 x = e^2 - 4
i mean subtract by 4 *
Time out.
The base is e. The exponent is 1 so we have: \[e^1=\sqrt{x+4}\]
Square both sides: \[e^2=x+4\]
So, can I substitute 2.71828 for e and give a numerical answer for x? If you have time for another one, I'd love help. :) \[e^\ln x^2 - 5^\log(5) 1\]
Subtract 4 from both sides.
That gives me 3.3891 right?
\[x=e^2-4=3.38\]
Yes
:)
u mean like this, for #2 |dw:1365474768137:dw|
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