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Simplify the expression. assume that all variables are real numbers.? 3√64(x+2)^3
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(4x+8)^3
how did you get that answer though? I cant seem to get the break down of it.
So we start here: 3√64(x+2)^3 3√64 = 4 so... 4(x+2)^3 Then expanding (x+2)^3 and multiplying it by 4 4x^3+24x^2+48x+32 Then you could find roots from there if you need those, the cubed root, is that only for the 64 or does that go over the (x+2) as well? If the cubed root was √(64(x+2)^3) then you would get a different answer then what I showed above.
so then it would be 4x+2 because the 3s cancel out. correct.
3√(64(x+2)^3) ^^If that is your equation, then the 64 goes to 4, so you get 4(x+2), then just distribute the 4 to get 4x+8
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