Question

calculate the molecular mass of the solute when 60.5 grams of a non-ionizing solute in 450 grams of water raises the boiling point to 101 degrees celsius

Answer 1

do you know what equation to use?

Answer 2

i think its ΔT b.p.=(0.515)(m)(i)

Answer 3

yep, thats exactly it.

all you need to do is a substitution and then an algebraic rearrangement.

molality=moles of solute/mass of solvent in Kg

for moles, n, sub in: moles =mass/molar mass (i.e. n=m/M)

Answer 4

im confused on how you do that

Answer 5

molality = moles/kg of solvent

sub in n=m/M

molality=(m/M)/kg of solvent

Answer 6

you have to rearrange to solve for M, molecular mass

Answer 7

ya im still lost....

Answer 8

lol \[\Delta T = i T _{b}m \rightarrow \Delta T = i T _{b}\frac{ \frac{ m }{ M } }{ kg _{solvent} }\]

Answer 9

remember m in the second equation means mass, not molality