Question

what is the equation in standard form? x^2+y^2-12x-12y+36=0

Answer 1

do you know the equation for standard form

Answer 2

idk if its an ellipse or what

Answer 3

its a circle and the equation would be (x - h)² + (y - k)² = r²

Answer 4

you can complete the square to write it in standard form do you know how to complete the square

Answer 5

i do not
waaaaa

Answer 6

okay Take half of 12, the coefficient of x, which is 6. Then square 6 and get 36.
Now add 36 to both sides:

x² + 12x + 36 + y² + 12y = -36 + 36

Complete the square on the y's:

Take half of 12, the coefficient of y,
which is 6. Then square 6 and get 36.
Now add 36 to both sides:

x² + 12x + 36 + y² + 12y + 36 = -36 + 36 + 36

Factor the first three terms as (x + 6)(x + 6) and as (x + 6)²
and combine the terms on the right

(x + 6)² + y² + 12y + 36 = 36

Factor the next three terms as (y + 6)(y + 6) and as (y + 6)²

(x + 6)² + (y + 6)² = 36

Now we compare with the standard form:

(x - h)² + (y - k)² = r²

And see that -h = +6 or h = -6, -k = 6, so k = -6, and r² = 36
so r = 6.

Answer 7

why thank you very much

Answer 8

your welcome:)