Question

HELP PLEASE

p x
2300 289
2000 302
1700 312
1500 325
1300 334
1200 342
1000 359

p=a+b lnx
whats a and b

Answer 1

If you use p=a+blnx, in the first row use:

2300=a+bln289 now solve for a

once you have that a

use the next row:

2000=a+bln302

plug the a you solve for up top in this equation, then you can solve for b, once you know b plug that back into your first equation to get a, does that make sense?

Answer 2

.... no sorry

Answer 3

don't let them fool you, lnx is just a number for this exercise don't look at it as a variable

Answer 4

im so lost...

Answer 5

So we have two equations:

1 -> 2300=a+bln289
2 -> 2000=a+bln302

If we have 2 equations and 2 unknowns we can solve one then substitute it into the other. Look at the equations like this: (this has the ln solved for)

1 -> 2300=a+b (5.666)
2 -> 2000=a+b (5.71)

Get equation 1 to be a = ....
Then plug that into equation 2 so you will only have b terms, then you can solve for a number for b, and plug back into 1 so you will only have a to solve for.

Answer 6

so a = 406?

Answer 7

Is your equation p=(a+b) lnx or p=a+(b lnx)? for the initial problem we are looking at?

Answer 8

the second 1 i think

Answer 9

So then...

1 -> 2300=a+b (5.666)
2 -> 2000=a+b (5.71)

Going from here, solving for a in 1 i get:

a=2300-(b*5.666)

Then i can plug this into the 2nd equation so:

2000= (2300-(b*5.666))+(b*5.71)

If you solve for b here I get b=~-6818
plug this back into:
a=2300-(b*5.666)
a=2300-(-6818*5.666)
a=~40,930

Does that make sense?

Honestly to me those numbers seem a little strange, but if the equation is setup the second way like you said that is what I got going through the math.

Answer 10

thx :)