Question

Use the quadratic formula to find any x-intercepts on the graph of the equation.

y=x^2+6x-1

Answer 1

do you know the formula?

Answer 2

no. unless its y=mx+b=c

Answer 3

no, the quadratic formula is...\[x=\frac{ -b \pm \sqrt{b ^{2}-4ac} }{ 2a }\]

Answer 4

okay so it's \[x= -6\pm \sqrt{6^2-4(10(-1)}/ 2(1)\]

Answer 5

sorry no 10 in the equation.

Answer 6

@HawkCrimson

Answer 7

the 10 should be a 1 but yeah thats right

Answer 8

then it's -6+- square root of 36- (-4)/ 2

Answer 9

correct :)

Answer 10

then -6+- sqrt 40 then how do you go from there?

Answer 11

dont forget that its over 2 still.

Answer 12

\[\frac{ -6\pm \sqrt{40} }{ 2 }\]

Answer 13

so you would work it out two ways...you would work it out adding the sqrt40 and subtracting the sqrt40

Answer 14

yes thank you for reminding me.

Answer 15

how would you subtract or add 40?

Answer 16

you would either find the actual sqrt or simplify it.

Answer 17

so that leaves us 6+- 2squareroot of 2/ 2