Find the value of 7 times x squared all over the square root of x to the fifth power. 7 times the square root of x, all over x. 7 over x. 7 times the square root of x. 7 times x all over the square root of x.
Alright, so we start with 7x^2/sqrt(x)^5 This can be simplified to 7x^2/x^(5/2) Then, separate the denominator to x^2*x^(1/2) You can then cancel out the x^2 in the numerator and the x^2 in the denominator, leaving you with x^(1/2) which is the same thing as sort(x) So, the final answer should be 7/sqrt(x)
So which choice would that be?
NEw best answer for who answers
Any takers?
got the answer of 7/sqrt(x). from the choices, what do you think would equal this when simplified?
just 7 over x?
or is that the answer?? i got 7 over x i just don't know if that is right
what happens when you have x^(1/2)/x ?
It stays the same
no. you get 1/(x^(1/2)) because (1/2)[from the numerator] - 1[from the denominator] = -1/2 x^(-1/2) = 1/(x^(1/2))
so what would be the wording for that?
Oh okayyy so the final answer is 7/sqrt(x)?
yes. just like what trogdortheburninator said. but i assume we are looking for the answer in sentence form. so that would be the first.
okay thank you so much!
I am about to put another one up can you walk me through it?
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