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lim(2e^x sinx) As x is approaching pi/2?
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Is this the product of 2e^x sin(x)?
@trogdortheburninator I'm not sure what the product of means.. It says to solve by substitution, so I would assume it's (2e^pi/2)*sin(pi/2), I'm just not sure as to what the e means in the equation.
use wolframalpha
then you should be set
\[\huge \lim_{x \rightarrow \frac{\pi}{2}}(2e^x\sin x)\] \[\huge =\lim_{x \rightarrow \frac{\pi}{2}} Use substitution for e^x.
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e is a number like pi which is used for integration and also for applying this number for other applications of calculus.
Sorry, different question!
By looking at it, I can see that sin(x) should go to 1, and e^x should go to whatever e^2pi is
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