I need a little bit of help understanding some springs. Suppose you and a class mate were to use identical springs, with identical hanging masses, but you pull the mass twice as far as your class mate. What happens to the period of oscillation?

Question

unklerhaukus · Answer

do you think the period of oscillation will change , or stay the same?

anonymous · Answer

I believe it would become greater because the amount of displacement undergone would be greater. But I am not sure if that is correct

unklerhaukus · Answer

Do you know a formula for the period of oscillation?

anonymous · Answer

would it happen to be: $$T=2\sqrt{\frac{ M }{ K }}$$ ?

And if so would that mean that the amount of displacement is irrelevant?

unklerhaukus · Answer

$$T=2\pi\sqrt{\frac mk}$$

unklerhaukus · Answer

that's right, the period of oscillation does not depend on initial conditions

anonymous · Answer

Ohhhh i just forgot the pi, thank you! I also have another question if you have time?

unklerhaukus · Answer

i can try ,

anonymous · Answer

two springs have the same natural length, but different spring constants, and they are made to stand upright on a table. Identical blocks of mass are placed on top of the springs and both blocks are stationary. IS the force exerted by the s1 less than or equal to s2? and is the springs constant of S1 greater than, less than, or equal to the springs constant of s2? See drawing

anonymous · Answer

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