Question

How much heat is lost by 2.0 grams of water if the temperature drops from 31oC to 29oC?
The specific heat of water is 4.184 J/g•oC.

Answer 1

A. 4.0 J
B. 6.2 J
C. 8.4 J
D. 16.7 J

Answer 2

i thinku know the equation \[H=ms(\theta _{2}- \theta _{1})\]

Answer 3

here H= heat loss by water
m= mass of water
s= specific heat of water

Answer 4

appreciated shamim

Answer 5

and \[\theta _{1}= \lower temperature= 29\]

Answer 6

so u got it

Answer 7

is not it

Answer 8

\[\LARGE Heat~ Lost=-mc(T_2-T_1)\]
\[\LARGE Heat Lost=mc(T_1-T_2)\](I removed the negative by reversing the brackets)
Substitute the values.

Answer 9

thanks shaminm n dls, this would help

Answer 10

welcome

Answer 11

:)