solve 3x^2-36x>0
i can try it to solve
thanks so much
\[3x ^{2}-36x>0\]
or,\[3x ^{2}>36x\]
or,\[x>12\]
take 3x^2-36x factor out 3x 3x(x-12)>0 x<0 or x>12
what happened t 3x outside the bracket
it was factored out
how???.
um, I don't really know how to explain this here, i'll explain it graphically instead.
okk
coz if u solve this q' on the casio class pad it gives u a way different answer
graph y=3x^2-36x look at where y=0 then look at where y<0
what answer does it give?
x-3.5, if rounded off
that's weird.
yeahhh.. so
ah, you forgot the x on the end. y=3x^2-36x
wt grade r u in, not 2 be personal
don't have 2 answer this
uu.. interesting
3x^2-36x>0 You can solve this just like a regular equation. To make it look a bit simpler, we can take the greater than sign and replace it with an equals sign for now. So 3x^2-36x=0. Since there is a x in both terms, we can divide it off and put it outside some parentheses. That gives you x(3x-12)=0. Go ahead and put the greater than back now. x(3x-12)>0. Now, you can look at it like two separate, smaller inequalities. x>0 and 3x-12>0. Now, you can solve both for x. x>0 is done already. To get the other, add 12 to both sides. 3x-12+12>0+12, 3x>12. Now divide both sides by 3. IMPORTANT: remember to always flip the inequality when you divide! So it becomes less than. 3x/3<12/3, x<4. So your answers are x>0, x<4. You can also combine them to get 0<x<4. That combined statement is probably the answer the Class Pad gave.
@singlesixx you got a bit of the math wrong, and we already figured out that the classpad gave the wrong answer because of operator error
What part of the math did I get wrong?
3x^2-36 is not the same as x(3x-12)
you factored the 3 out of the 36 but not out of the 3x
Wow. I am not the smartest person. I had 3x(3x-12), and changed it to what's there now.
it's fine, anyone could have made that mistake
it's just a calculation error, your theory was right.
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