MAth
A circle has a radius of 13 centimeters. If one-half of the circle is cut away, what is the area of the remaining portion? (Use 3.14 for .) A. 20.41 cm2 B. 1,061.32 cm2 C. 265.33 cm2 D . 530.66 cm2
C
13. At Bud's company, bowling balls are composed of a sphere with a diameter of 8 inches. If a store receives a shipment of 24 bowling balls, what is the total volume of the balls? A. 1,607.68 cubic inches B. 20,192.46 cubic inches C. 267.95 cubic inches D. 6,430.72 cubic inches
wait never mind!!!!
@Noemi95 are you sure ?
okay
basically all you do is find the area of the hole circle which is 530.66 then divide it by 2
no wait yeah I am right
because all you need is one radius to find area
19.Hal's parents recently built a rectangular swimming pool that measures 7 meters long, 7 meters wide, and 1 meter deep. If the pool is 77% full, how much more water is needed to finish filling the swimming pool? A. 37.73 cubic meters B. 3.08 cubic meters C. 11.27 cubic meters D.74.76 cubic meters
the equation for finding the are area of a circle is A=(pi) * r^2 So we plug in the values, A= 3.14 * 13^2 =530.66 (whole) so we now divide by 2, and we get 265.33 (For the first one)
Thanks . What about the next one number 13 ? P.s I promise to give you a medal lol
haha okay let me see
Volume a sphere = 4/3 pi r * r * r then times 24
I think it's D
The equation IS the one RadEn told you, so we plug in values and we get V=(4/3) * 3.14 * 4^3 we solve that and we get, 267.94667 then multiply times 24 and the answer is 6,430.72
agreed ^
Thank you .What about 19 ??
The formula is V= length*width* height So let's plug in values, V=7*7*1=49 is the TOTAL volume, but we only want to know 77% of that
100% - 77% = 23% that's the rest to get full so, u need 23/100 of full volume what's 23/100 * 7 * 7 * 1 assumed that rectangular swimming pool like a cuboid
so now we divide 49 by 100, and we get 0.49 and we multiply by 77= 37.73
I agree with Rad, so @RadEn explanation is more proper, go with that one!(:
Thank yall both
B) 61
At his trucking company, Paul received an order to ship 251 cubic feet of oil in cylindrical steel barrels. If each barrel has a radius of 1.5 feet and is 5 feet tall, how many steel barrels will Paul need? A. 9 B. 6 C. 8 D. 7
Equation : V=l*h*w plug in values, V= 5*5*5 (same measures because it's a cube) we get V=125 and they tell us they still have 64 cubit feet left, so 125-64=61
thank you.
Volume a cube = s * s * s here given s = 5 so, volume of thoy box = 5 * 5 * 5 = 125 known the rest space of box = 64 so, the space block filled 125-64=127
oppss mis-co-vaste, haha :) 125-64=61
thank you . can you tell me number 28 ?
where is it ?
in the word document
ah still in the same file --"
yes .
volume = length * width * height volume is given = 300 in^3 , length = 15, width = 4 length * width * height = 300 15 * 4 * H = 300 solve for H
15 * 4 * H = 300 60H = 300 divide by 60 from both sides: 60H/60 = 300/60 H = 5
Thank you so much . I still need help but so that I can give you a medal im going to close this on and open another box .
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