Question

Which Value(s) of X are excluded from the solution to the following equation ? Show all of your work to get to your solution .

x^2-5x-20 x 2
----------------- = -------- + --------
x^2-17x+70 x-10 x-7

Answer 1

I got this

Answer 2

Do you know how to factorize a given polynomial??

Answer 3

No, i dont know how to factorize a given polynomial. @waterineyes

Answer 4

What will you put as value of x in the denominator so that you will get 0 in the denominator??

Answer 5

\[\frac{ x^2-5x-20 }{ x^2-17x+70 }=\frac{ x }{ x-10 }+\frac{ 2 }{ x-7 }\]

Answer 6

See, I think we need not to calculate x here, we just want that what values of x should be excluded so that we can have well defined values of x in this question.

Answer 7

@Forever_Me , you know that you can't divide by zero?

Answer 8

Yep..
Division by zero should be avoided, as we can't do this..

Answer 9

find the values of x so that
x-10=0
x-7=0
x^2-17x+70=0

Answer 10

In RHS, we have:
\[\frac{1}{x - 10}\]

Can you tell us that for what value of x, denominator (x-10) will be zero??

Answer 11

Yes , i know we cant divide by Zero @Peter14

Answer 12

WOuld you mind explaning exactly what you want me to do . @waterineyes

Answer 13

Just put (x-10) = 0

So you will get:
\[x - 10 = 0\]

So what will be x, can you tell?

Answer 14

Hey, you have to just do the calculation.
Add 10 both the sides and find x..

Answer 15

So x= 10 ? @waterineyes