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Mathematics 20 Online
OpenStudy (anonymous):

write x=sin theta, y= tan theta to eliminate theta.

OpenStudy (ash2326):

\[x=\sin \theta\] \[y=\tan \theta\] Divide first by second \[\frac x y= \frac {\sin \theta}{\tan \theta}\] @sophie14 what would you get on the right hand side?

OpenStudy (anonymous):

cos theta ?

OpenStudy (ash2326):

good, so we have \[\frac x y =\cos \theta\] Now there is an identity \[\sin^2 \theta+\cos^2 \theta=1\] Plugin the values of sin theta and cos theta, and voila!

OpenStudy (anonymous):

hmm I do not understand

OpenStudy (ash2326):

\[\sin^2 \theta+\cos^2 \theta=1\] sin theta= x cos theta =x/y so \[x^2+\frac {x^2}{y^2}=1\] so theta is eliminated, you can simplify this further

OpenStudy (anonymous):

how do you simplify this futher?

OpenStudy (ash2326):

\[x^2(1+\frac 1 {y^2})=1\] \[x^2(\frac{1+y^2}{y^2})=1\] \[x^2=\frac{y^2}{1+y^2}\]

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

how do I get theta= with sintheta= sin 15

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