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write x=sin theta, y= tan theta to eliminate theta.
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\[x=\sin \theta\] \[y=\tan \theta\] Divide first by second \[\frac x y= \frac {\sin \theta}{\tan \theta}\] @sophie14 what would you get on the right hand side?
cos theta ?
good, so we have \[\frac x y =\cos \theta\] Now there is an identity \[\sin^2 \theta+\cos^2 \theta=1\] Plugin the values of sin theta and cos theta, and voila!
hmm I do not understand
\[\sin^2 \theta+\cos^2 \theta=1\] sin theta= x cos theta =x/y so \[x^2+\frac {x^2}{y^2}=1\] so theta is eliminated, you can simplify this further
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how do you simplify this futher?
\[x^2(1+\frac 1 {y^2})=1\] \[x^2(\frac{1+y^2}{y^2})=1\] \[x^2=\frac{y^2}{1+y^2}\]
thanks
how do I get theta= with sintheta= sin 15
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