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Mathematics 19 Online
OpenStudy (anonymous):

Keith's long jump distances in feet from the last 3 track meets:23.8, 23.0 ,22.6 ,24.2 ,23.8 ,22.5 ,23.1 ,24.0. What is the standard deviation? please help me work this out !

OpenStudy (anonymous):

to find standard deviation you need to find two things before it. do you know what?

OpenStudy (anonymous):

mean and range

OpenStudy (anonymous):

mean=23.4 range=1.7 median=23.5

OpenStudy (anonymous):

good, so whats the mean?

OpenStudy (anonymous):

ok so the mean is 23.4, what do you do next?

OpenStudy (anonymous):

Do you take the mean and square it by each of the distances

OpenStudy (anonymous):

perfect! thats called variance....so (23.8-23.4)^2 + (23-23.4)^2 +.....

OpenStudy (anonymous):

after you calculated that you divide your answer by the number of pieces of data, so in this case 8

OpenStudy (anonymous):

oh ok let calculate of these and I will get back with you in a few min.

OpenStudy (anonymous):

thats fine, im doing it too so we can compare answers

OpenStudy (anonymous):

ok so heres what i got: Variance= (3.02)/(8) variance = .3775 to find standard deviation, you take the square root of the variance sqrt(.3775) = .614 so the standard deviation = .614

OpenStudy (anonymous):

you're going to want to follow that same procedure for any other types of problems like that

OpenStudy (anonymous):

ok thanks for you help

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