What is the value of "h' in the function y=2^(x+1) ?

Question

tkhunny · Answer

There is no "h".  Please ask a better or more complete question.

freethinker · Answer

you are quite persistent knowing the value of "h" :)

freethinker · Answer

http://openstudy.com/study#/updates/51688289e4b0344769c98110 here is your previous post :P

anonymous · Answer

Thats all there giving , so thats all that im asking. Please dont act rude !

anonymous · Answer

And Lol Me ?? No my teacher is . @freethinker

jim_thompson5910 · Answer

If you start with 

y = 2^x

then you can translate, dilate, reflect etc using this form

y = a*2^(x-h) + k

where

the variable a handles dilation/compression and reflection

h does horizontal translation

k does vertical translation

anonymous · Answer

@tkhunny 
SEE !

anonymous · Answer

And what might that be ? @freethinker

jim_thompson5910 · Answer

y=2^(x+1)

y=1*2^(x+1)

y=1*2^(x+1) + 0

y=1*2^(x-(-1)) + 0

Compare this to y = a*2^(x-h) + k