Question

I don't want the answer I would just like help doing it, Please!
The graph of which equation has a vertex of (1, –3)?
y = 1(x – 3)2 + 1
y = 2(x – 3)2 + 1
y = 2(x – 1)2 – 3
y = 2(x + 1)2 – 3

Answer 1

Hint:

y = a(x-h)^2 + k

has the vertex of (h, k)

Answer 2

So

y = 1(x – 3)^2 + 1

for instance is in vertex form y = a(x-h)^2 + k where

a = 1
h = 3
k = 1


So the vertex is (3, 1), which rules out choice A

Answer 3

@jim_thompson5910 would the answer be D?

Answer 4

y = 2(x + 1)^2 – 3

y = 2(x - (-1))^2 – 3

it's now in the form y = a(x-h)^2 + k where

a = 2
h = -1
k = -3

So the vertex of this is (-1, -3)

Answer 5

so close, just had the wrong sign for the x coordinate of the vertex

Answer 6

so then it would be c?

Answer 7

yep

Answer 8

Thank you :)

Answer 9

yw