what is the lenght height and width of a rectanguar prism if they are in a ratio of 6:4:3 and the volume is 810
what is 6*4*3?
or rather; 6n * 4n * 3n = 810
no its like the ratio, its 6:4:3
so I need to find the measurments of each side by using those ratios
the sides l:h:w have a ratio of 6:4:3 volume of a prism is defined as l*h*w = 810 the only difference between the actual lengths, and the ratio, are some constant scaled factor.
therefore, we know: length = 6n height = 4n width = 3n and 6n*4n*3n = 810 solve for n
ohh thank you but I made a mistake, the surface area is 810 and I need to find the volume of the rectangular prism
...... same concepts, different "formula" tho can you recall a good formula for surface area?
6n*4n*3n = Volume is still fine, and still have to determine the n value
2ab+2bc+2ac right?
sounds about right, but lets use lhw instead of abc
so my equation would be 6n*4n*3n= 2lw+2wh+2hl ?
2hl + 2hw + 2lw = 810 no, one formula is for surface area, and one is for volume. they will not generally equate to the same value
lhw 643 2lw+2wh+2hl = 810 2(6n)(3n)+2(3n)(4n)+2(4n)(6n) = 810
2(6n)(3n)+2(3n)(4n)+2(4n)(6n) = 810 36n^2 + 24n^2 + 48n^2 = 810 108n^2 = 810 n^2 = 810/108
ohhhhh wait why would you square the numbers?
so what does n represent?
btw thank you so much for helping!!
n represents the number that is scaling the ratio of 6:4:3 to its proper lengths
so after I find n what do I do?
i thought i covered that
length is equal to 6n height is equal to 4n width is equal to 3n
once you find n, you know that actual measurements and not just their ratio
ooohhhh I get it wait so n would be 7.5?
dunno, i aint got me calculator to find the sqrt of (810/108) but ill trust you on it
wait why would you find the square root?
you plug in the values for length width and height into the surface area formula and solve for n 2(6n)(3n)+2(3n)(4n)+2(4n)(6n) = 810 36n^2 + 24n^2 + 48n^2 = 810 108n^2 = 810 n^2 = 810/108
wait is it possible to do a square root of a decimal?
its possible to do the sqrt of any real number. it all depends on what you define as an acceptable output
ohhh so I got 2.738612788 so would I just round it to the nearest tenth?
rounding introduces a small error, the longer the decimal the smaller the error. so its up to you how far you want to take this in the end. my thought was to have 4 decies
does the solution ask for an approxiamte, or an exact value?
yeah it asks for an exact volume
then do not round to anything :)
you can simplify to:\[n=\sqrt{\frac{15}{2}}\]
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