Question

What are the first five terms in the arithmetic sequence An=6n, starting with n=1? I am thinking it is 7,8,9,10,11, but I am not sure

Answer 1

what is 6n, when n=1?
what is 6n, when n=2?
what is 6n, when n=3?
...
what is 6n, when n=5?

Answer 2

OH!! I see! Not as hard as I thought! I have never seen this before tho. Thank you!

Answer 3

i recall the first time i seen it. it does take a little bit of getting used to :)

Answer 4

ok so if I have the first five terms in the geometric sequence An=(2)^n-1 what the heck does that mean?

Answer 5

all your doing is plugging n=1,2,3,4,5 into the spot reserved for the n, and evaluating

Answer 6

so it would be 2, 4, 8, 16, 64?

Answer 7

close; hard to read the ascii notation

\[2^{n-1}\]
or
\[2^n-1\]
???

Answer 8

\[2^{n-1?} when n=1\]

Answer 9

when n=1

Answer 10

then the output is simply
\[2^{n-1}=2^0,2^1,2^2,2^3,2^4\]

Answer 11

ah I get it! Thank you! Boy that just sounded a lot harder than it was

Answer 12

if you are better used to playing with functions of x, instead of n, the name of the variable doesnt matter.

\[f(x)=2^{x-1}~;~x=1,2,3,4,5\]is the same thing

Answer 13

\[\sum_{k}^{5?}=then \it has a little 1 then a k \in the \middle and a little 2 \above that and I have never seen that symbol either\]

Answer 14

\[\sum_{k}^{5?}=\]then \it has a little 1 then a k \in the \middle and a little 2 \above that and I have never seen that symbol either

Answer 15

might be better to use the draw feature if the equation editor is giving you issues :)

Answer 16

the symbol "\(\sum\)" is just a greek capital letter "S", and represents the SUM of a stated rule or expression.