Question

Linear inequalities question?

Answer 1

Here is the problem

Answer 2

x = # of bears
y = # of dogs

Answer 3

bears cost $6 each, so x of them cost 6x dollars

dogs cost $4 each, so y of them cost 4y dollars

Answer 4

all together, x bears and y dogs cost a total of 6x+4y dollars

Answer 5

what's next?

Answer 6

I got up to there

Answer 7

if c is the total cost, then c must be between 80 and 170, so

80 <= c <= 170

Answer 8

it says it needs to be not more then $170 but at least $80

Answer 9

okay

Answer 10

the 2nd equations would have to be 6x + 4y = c

Answer 11

the total cost is c = 6x+4y

Answer 12

so...

80 <= c <= 170

80 <= 6x+4y <= 170

Answer 13

80 <= 6x+4y <= 170

80 <= 2(3x+2y) <= 170

80/2 <= 2(3x+2y)/2 <= 170/2

40 <= 3x+2y <= 85

Answer 14

Okay I got it thanks!!

Answer 15

yw

Answer 16

would I do the same thing for this problem

Answer 17

oh wait, they want 2 inequalities, so you have to break 80 <= 6x+4y <= 170 up into

6x+4y >= 80

and

6x+4y <= 170

Answer 18

yes you would