Question

Simplify the expression below.

Select one of the options below as your answer:
A. 2x^3 + 3x
B. 3x^2 - 15
C. 6x^2 + 8x
D. 7x^2 - 4x

Answer 1

12x^3 - 14x^2 - 40x / 2x-5

Answer 2

thats the problem^

Answer 3

no

Answer 4

yes

Answer 5

nope

Answer 6

the thing 2 minutes ago

Answer 7

ya

Answer 8

ya, and im dumb

Answer 9

First factor 2x out of the numerator like this:\[\frac{ 12x^3-14x^2-40x }{ 2x-5 }=\frac{ 2x(6x^2-7x-20) }{ 2x-5 }\]Now factor the quadratic in the numerator:\[\frac{ 2x(6x^2-7x-20) }{ 2x-5 }=\frac{ 2x(6x^2-15x+8x-20) }{ 2x-5 }=\frac{ 2x[3x(2x-5)+4(2x-5)] }{ 2x-5 }\]\[=\frac{ 2x(3x+4)\cancel{(2x-5)} }{\cancel{ 2x-5} } =2x(3x+4)=...?\]Do you understand what happened there? We first factored 2x from numerator. Then we factored the remaining quadratic and got 2x-5 in the numerator and denominator so we cancelled those out. We are left with an expression now which can be expanded.

Can you expand the remaining expression and tell me what the answer is?

@Keandrap15

Answer 10

Oh for heavens sake!!! Now the genius will take over. Good luck

Answer 11

lol wat

Answer 12

none of what u just said makes sense.

Answer 13

I don't know who you are referring to...*cough cough*

Answer 14

i dont understand any of what u said in the long paragraph.. i cant learn how to do a problem like this in a paragraph like that @Mertsj was helping just fine

Answer 15

@Mertsj

Just take over lol. I'm sorry for causing any disturbances. He appears to be more comfortable with whatever you were doing =D

Answer 16

sorry if i sound mean im just frustrated right now and i feels so dumb

Answer 17

@genius12 Toooooooooooooooooooooooooooooooooooooo Late
You wanted it. You got it

Answer 18

lolololol you meanie @Mertsj

Answer 19

just forget it then damn

Answer 20

@Keandrap15
I'll just help you out then. What part of my explanation did you not understand?

Answer 21

are you there @Keandrap15

Answer 22

sorry guys im stupid and dont know how to do these kind of problems

Answer 23

anyone gonna help me please

Answer 24

nvm i guessed the answer

Answer 25

got more to answer like this one

Answer 26

now \[\frac{ (12x ^{3}-14x ^{2}-40x) }{ 2x-5 }\]

Answer 27

your aim is to factorize above and have answers such that one of the answers can cancel out 2x-5 under

Answer 28

factorize 2x from above

Answer 29

\[\frac{ 2x(6x ^{2}-7x-20) }{ 2x-5 }\]

Answer 30

now we factorize the quadratic equation in bracket above