Question

8x^3-10x^2-25x/4x^2+5x

Answer 1

A. 3x2 + 2x
B. 4x - 10
C. 2x - 5
D. 3x + 2

Answer 2

@jim_thompson5910

Answer 3

\[\frac{ 8x ^{3}-10x^{2}-25x }{ 4x ^{2}+5x }\]First we can cancel an x from each term:\[\frac{ 8x ^{2}-10x-25 }{ 4x+5 }\]

Answer 4

Then I think you have to evaluate which each solution the inequality to see which one gives you 0=0

Answer 5

from there you factor 8x^2-10x-25


8x^2-10x-25


8x^2+10x-20x-25


(8x^2+10x)+(-20x-25)


I'll let you finish up the factorization

Answer 6

How did you do that factorization?

Answer 7

Ohhhh no I just saw it :)

Answer 8

would it be B?

Answer 9

what do you get when you finish up the factorization

Answer 10

Let me help you, you need to find the common factor of the tarms that jim put in parenthesis to take them out of the equation.

Answer 11

i got (-5+-4x)(5+-2x)

Answer 12

so its c

Answer 13

you somehow introduced a negative when there isn't supposed to be one

it should be (4x+5)(2x-5)

Answer 14

yeah it's C

Answer 15

yeah. thanks