A company offers a starting salary of $33,000 with raises of $3,500 per year. Find the total salary over a 10 year period.

Question

anonymous · Answer

you up for a word problem ? @e.mccormick

anonymous · Answer

What you want to find is
33000 + (33000+3500) + (33000+3500*2) + (33000+3500*3) + ... + (33000+3500*9)

If you learned Arithmetic Sequence Formula,
starting term is 33000
difference between terms is 3500
there are 10 terms

So, the answer would be
$$\frac{n(2a+(n-1)d)}{2}=\frac{10(66000+9*3500)}{2}=487500$$

e.mccormick · Answer

@angelina22309 Hey there.  I have been going over area formulas with determinants...  so Idid not see your message.  How are you doing on this one?  Did what nightwill put up make sense?

anonymous · Answer

It did make sense but the answer is actually $48,750

anonymous · Answer

@e.mccormick

anonymous · Answer

wait!

anonymous · Answer

Nevermind I forgot the 10 so yea hes right

e.mccormick · Answer

Yah, the total salary would be what you were paid over all 10 years.  The salary AFTER 10 years is a different question.