Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

For the equation given below, evaluate y' at the point (−12). 5xy−4x+6=0

OpenStudy (anonymous):

implicit differentiation

OpenStudy (anonymous):

yeah i tried it and i get 5dy/dx =4 and i know i am suppose to divide by 5 but then i dont know where to plug in my point (-1,2)

OpenStudy (anonymous):

\[5xy'+5y-4=0\]

OpenStudy (anonymous):

you solve 5xy as a product

OpenStudy (anonymous):

oh so im suppose to do the product rule

OpenStudy (anonymous):

any time you differentiate x then y is like a constant

OpenStudy (anonymous):

when you differentiate y then x is like a constant followed by y'

OpenStudy (anonymous):

okay thank you

OpenStudy (anonymous):

my answer is different from yours

OpenStudy (anonymous):

absolutely\[Vdu+Udv\]

OpenStudy (anonymous):

NOW YOU PUT YOUR VALUES

OpenStudy (anonymous):

okay do you think you can check my answer i think i need to do it again

OpenStudy (anonymous):

\[5(-1)y'+5(2)-4=0\]

OpenStudy (anonymous):

BODMAS is important here

OpenStudy (anonymous):

\[-5y'+10-4=0\]

OpenStudy (anonymous):

so my final answer was 6/5 is that correct

OpenStudy (anonymous):

\[y'=\frac{ 6 }{ 5}\]

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
kaelynw: starting to draw a hand
1 day ago 16 Replies 2 Medals
Twaylor: Rate it :D (Took 2 days)
2 days ago 7 Replies 0 Medals
XShawtyX: Art, Short Writing Assignment: Imagining Landscapes
1 hour ago 6 Replies 1 Medal
XShawtyX: Chemistry, Help ud83dude4fud83cudffe
2 days ago 13 Replies 1 Medal
kaelynw: tried a lil smt, the arm is off but i like the other stuff
3 days ago 27 Replies 3 Medals
kaelynw: art igg
3 days ago 14 Replies 1 Medal
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!