In the triangle above, W equals 12 cm, X equals 6 cm, Y equals 6 cm, and Z equals 4 cm. A triangle with which of the following dimensions would have the same area? A. W = 12, X = 7, Y = 6, Z = 2 B. W = 24, X = 7, Y = 6, Z = 2 C. W = 24, X = 7, Y = 6, Z = 4 D. W = 10, X = 6, Y = 5, Z = 4
not 100% sure, but is W equal to half of the base length? or the full base length? seems a bit ambiguous to me
full base >.<
ok thanks for clearing that up
no problem ;~; do you have an answer? D;
still trying out a few things, one sec, sry
thank you cx
just wanted to see how or why they threw in X and Y, but it looks like they're just extra values that don't really factor in If W is the entire base, then the area of the original triangle is A = b*h/2 A = W*Z/2 A = 12*4/2 A = 48/2 A = 24 So the original area is 24 square units We want a triangle with different values of W and Z to also have an area of 24 square units. It turns out that if we double one dimension and take half of the other dimension, then we keep the area the same. So double W = 12 to get W = 24. Take half of Z = 4 to get Z = 2 Notice how the area is unchanged A = b*h/2 A = W*Z/2 A = 24*2/2 A = 48/2 A = 24 So the answer is B. W = 24, X = 7, Y = 6, Z = 2
Thank you!^___^
sure thing
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