A bank account earns 5% annual interest compounded continuously. A) assuming that money is continuously withdrawn from the account at a rate of 11000 per year, write a differential equation describing the balance (b) in dollars, in the account (where b is a function of t, measured in years) B)assuming that money is conitnously deposited into the account at a rate of 11000 per year, write a differntial equation describing the balance B (in dollars) in account ( where B is a function of t, measured in years)
been stuck on this all week thank you i assume we take deverivate for one and anti dervative for other
but not sure? Thanks for helping out!
I'm having the same problem with one I posted hours ago... B'(t)= rate of continuous compounding \[f(b)=11000e ^{0.05b}\] \[^{} \int\limits_{0}^{n} B\prime(t)(e ^{-0.05t})dt\] so take the derivative of the first part then inegrate the entire thing by parts? \[\int\limits_{0}^{t}[(11000e ^{0.05t})\prime (e ^{-0.05t})]dt\]
wait I think the variables are wrong but instead of t use b?
balance due to continuous compounding: \[b(t)=Pe^{0.05t}\] but principal = previous year "b"-11000
what do you mean?
\[b(t)=\left[b(t-1)-11000\right]e^{0.05t}\]
?so the other would look like [b(t-1)+11000]e^(.05t)
and this means b is a function of t as well?
it is given that "b" is a function of "t"
does the question say "differential" equation or "difference" equation??
so this work is on iterguals and anti dervitaives so this wouldnt even show up ? i guess thats what confused me
no. no integration
write a diferential equation describing balance B (in dollars) in the account (where B is a function t, measured in years)
so for part A it asked Assuming that money is continuously WITHDRAWN from the account at a rate of $11000 per year, write a DIFFERENTIAL equation describing the Balance B( in dollars) in the account where B is a function of t, measured in years)
and the next part 2 would be Deposited instead of withdawn
@ electrokid why not? it's over an period of time. Just trying to understand so I can understand my prob w/ CAPITAL VALUE I posted hours ago
so now that i confirmed it is a Differential equation does that change the results?
differential means, in derivative form defference means -> in the above b(t-k) form..
@TARAMAYO I did not see your previous post. this problem, does not require integration
yea so its DIFFERENTIAL so what would the new equation be then? and how would i solve it with a withdraw or an deposit?
so how would the new formula look for my equation?
so confusing I hate word probs, why wouldn't a negative rate suffice? as it wud in an equation for the rate of decay?
\[{d\over dt}b(t)=0.05b(0)-11000\\ b'(t)=0.05b(0)-11000 \] b(0) = balance at t=0
if money is continuously added, you make +11000
rate is always positive since the interest is always added :)
follow people?
im kinda following?
so what would we do if we had money being withdrawn?
the above equation was for "withdrawal" if money is added yearly, you make it +11000 instead of -11000
shouldnt the .05 be negative? because lets say I have 100,000 taken out each year wouldnt i lose money if i always took out 11000?
if my rate of change is withdrawling 11000?
no.. the interest rate is always positive.. has nothing to do with withdrawal interest amount is always added!!!
haha okay cool , just weird not taking the anti derivative
to find the composite function b(t), you take the anti derivative.. but that is not what the question is asking for!!
it wants to know what B'=
but not B(t) just B'=? for withdrawn and deposited
since we have 0.05b(0)−11000 wouldnt that just be -11000 or +11000 because .05(b(0))
where do we put the b at since it says the variable b is not defined?
it just wants to know what B'=?
correct, just the b'(t), and not b(t)
??
so the answer is just -11000 and +11000?
Pe^rt
WHAT!!no your answer would mean that there is no "continuous compounding at all1!!!!!"
ahhahah HELP ME!!! lol
lol so how would i write this bad boy out?
what was the balance at t=0?
0.05b(0)−11000? it wants a function of B'=?
no, it wants THE funtion b'(t)
ill send the original equation!!!!
let me upload it real fast!
@dmariscal hurry up. Its 2:30am
i'm not making this up electrokid, this is the formula sheet I got from my instructor (last formula) -- negative rate. I'm not pretending I know what I'm doing but I dont understand either.
okay!!!
okay this is the question and the first part that is covered is the same as part 2 just wants the amount when it is withdrawn
this should be clear now Thanks SO MUCH!
@TARAMAYO its opposite :) the formula is to find "present" from future... we are finding future/present from past
???
ohh thats for him!!! What about mine!!! i sent a screen shot!! so its more clear!!
@dmariscal you are in a test. and I have given enough information already, unknowlingly. this is against the code of conduct of the website and unethical. good luck.
the time expired
if you saw this was a screen shot form earlier today at noon
i just wanted to see how to solve it, i already failed the test
isee. :) ok
@ dmariscal are you taking business calc? when do you have to get this prob done? Holy smokes I just read electrokid's response
so, yes. what we did was right.
how did we put it into terms of B(t) so t would be in our awnser?
@TARAMAYO to be able to use the "@" tool correctly, you should not put a "space" after that "@" symbol.
@electrokid so can you tell me what's my R(t) here? I've been waiting for hours, but if it's too late I'm going to the tutoring center tomorrow. Thanks.. CAPITAL VALUE: Suppose income from an investment starts (at time 0) at $6,000 a year & increases linearly & continuously at a rate of $200 a year. Find the Capital Value at an interest rate of 5% compounded continuously. Improper integral using R(t)e^(-rt)... Which amount is the R(t)? & what makes the other amount in this problem?
@dmariscal then instead of b(0), put b(t) :) \[{\rm withdrawal:}\;B'(t)=0.05B(t)-11000\\ {\rm deposit:}\;B'(t)=0.05B(t)+11000 \]
@TARAMAYO I am looking at it now..
@electrokid you know what, nevermind, it's really late I've got to get up in 3hrs for work
@TARAMAYO so, your rate is, +200 a year
@electrokid Hey super thanks, I appreciate it! gnite!
thanks so much
one last question wouldnt it be .06t+11000
then, its a linear increase.. so, \[ CV=\int I'(t)e^{-rt}dt=\int 6000e^{-0.05t}dt \]
the intrest + the intial ? so why would B(t) be in there
@dmariscal coz, you get some compound interest on whatever the balance you had at time t.. i.e., a lilttle compount intertest of 0.05B(t)
okay cool!!
Thanks again i wish i could pay you on this sight!!
haha. np. ☮
@dmariscal didn't see you on yesterday so here it is
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