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Mathematics 23 Online
OpenStudy (anonymous):

A bank account earns 5% annual interest compounded continuously. A) assuming that money is continuously withdrawn from the account at a rate of 11000 per year, write a differential equation describing the balance (b) in dollars, in the account (where b is a function of t, measured in years) B)assuming that money is conitnously deposited into the account at a rate of 11000 per year, write a differntial equation describing the balance B (in dollars) in account ( where B is a function of t, measured in years)

OpenStudy (anonymous):

been stuck on this all week thank you i assume we take deverivate for one and anti dervative for other

OpenStudy (anonymous):

but not sure? Thanks for helping out!

OpenStudy (anonymous):

I'm having the same problem with one I posted hours ago... B'(t)= rate of continuous compounding \[f(b)=11000e ^{0.05b}\] \[^{} \int\limits_{0}^{n} B\prime(t)(e ^{-0.05t})dt\] so take the derivative of the first part then inegrate the entire thing by parts? \[\int\limits_{0}^{t}[(11000e ^{0.05t})\prime (e ^{-0.05t})]dt\]

OpenStudy (anonymous):

wait I think the variables are wrong but instead of t use b?

OpenStudy (anonymous):

balance due to continuous compounding: \[b(t)=Pe^{0.05t}\] but principal = previous year "b"-11000

OpenStudy (anonymous):

what do you mean?

OpenStudy (anonymous):

\[b(t)=\left[b(t-1)-11000\right]e^{0.05t}\]

OpenStudy (anonymous):

?so the other would look like [b(t-1)+11000]e^(.05t)

OpenStudy (anonymous):

and this means b is a function of t as well?

OpenStudy (anonymous):

it is given that "b" is a function of "t"

OpenStudy (anonymous):

does the question say "differential" equation or "difference" equation??

OpenStudy (anonymous):

so this work is on iterguals and anti dervitaives so this wouldnt even show up ? i guess thats what confused me

OpenStudy (anonymous):

no. no integration

OpenStudy (anonymous):

write a diferential equation describing balance B (in dollars) in the account (where B is a function t, measured in years)

OpenStudy (anonymous):

so for part A it asked Assuming that money is continuously WITHDRAWN from the account at a rate of $11000 per year, write a DIFFERENTIAL equation describing the Balance B( in dollars) in the account where B is a function of t, measured in years)

OpenStudy (anonymous):

and the next part 2 would be Deposited instead of withdawn

OpenStudy (anonymous):

@ electrokid why not? it's over an period of time. Just trying to understand so I can understand my prob w/ CAPITAL VALUE I posted hours ago

OpenStudy (anonymous):

so now that i confirmed it is a Differential equation does that change the results?

OpenStudy (anonymous):

differential means, in derivative form defference means -> in the above b(t-k) form..

OpenStudy (anonymous):

@TARAMAYO I did not see your previous post. this problem, does not require integration

OpenStudy (anonymous):

yea so its DIFFERENTIAL so what would the new equation be then? and how would i solve it with a withdraw or an deposit?

OpenStudy (anonymous):

so how would the new formula look for my equation?

OpenStudy (anonymous):

so confusing I hate word probs, why wouldn't a negative rate suffice? as it wud in an equation for the rate of decay?

OpenStudy (anonymous):

\[{d\over dt}b(t)=0.05b(0)-11000\\ b'(t)=0.05b(0)-11000 \] b(0) = balance at t=0

OpenStudy (anonymous):

if money is continuously added, you make +11000

OpenStudy (anonymous):

rate is always positive since the interest is always added :)

OpenStudy (anonymous):

follow people?

OpenStudy (anonymous):

im kinda following?

OpenStudy (anonymous):

so what would we do if we had money being withdrawn?

OpenStudy (anonymous):

the above equation was for "withdrawal" if money is added yearly, you make it +11000 instead of -11000

OpenStudy (anonymous):

shouldnt the .05 be negative? because lets say I have 100,000 taken out each year wouldnt i lose money if i always took out 11000?

OpenStudy (anonymous):

if my rate of change is withdrawling 11000?

OpenStudy (anonymous):

no.. the interest rate is always positive.. has nothing to do with withdrawal interest amount is always added!!!

OpenStudy (anonymous):

haha okay cool , just weird not taking the anti derivative

OpenStudy (anonymous):

to find the composite function b(t), you take the anti derivative.. but that is not what the question is asking for!!

OpenStudy (anonymous):

it wants to know what B'=

OpenStudy (anonymous):

but not B(t) just B'=? for withdrawn and deposited

OpenStudy (anonymous):

since we have 0.05b(0)−11000 wouldnt that just be -11000 or +11000 because .05(b(0))

OpenStudy (anonymous):

where do we put the b at since it says the variable b is not defined?

OpenStudy (anonymous):

it just wants to know what B'=?

OpenStudy (anonymous):

correct, just the b'(t), and not b(t)

OpenStudy (anonymous):

??

OpenStudy (anonymous):

so the answer is just -11000 and +11000?

OpenStudy (anonymous):

Pe^rt

OpenStudy (anonymous):

WHAT!!no your answer would mean that there is no "continuous compounding at all1!!!!!"

OpenStudy (anonymous):

ahhahah HELP ME!!! lol

OpenStudy (anonymous):

lol so how would i write this bad boy out?

OpenStudy (anonymous):

what was the balance at t=0?

OpenStudy (anonymous):

0.05b(0)−11000? it wants a function of B'=?

OpenStudy (anonymous):

no, it wants THE funtion b'(t)

OpenStudy (anonymous):

ill send the original equation!!!!

OpenStudy (anonymous):

let me upload it real fast!

OpenStudy (anonymous):

@dmariscal hurry up. Its 2:30am

OpenStudy (anonymous):

i'm not making this up electrokid, this is the formula sheet I got from my instructor (last formula) -- negative rate. I'm not pretending I know what I'm doing but I dont understand either.

OpenStudy (anonymous):

okay!!!

OpenStudy (anonymous):

OpenStudy (anonymous):

okay this is the question and the first part that is covered is the same as part 2 just wants the amount when it is withdrawn

OpenStudy (anonymous):

this should be clear now Thanks SO MUCH!

OpenStudy (anonymous):

@TARAMAYO its opposite :) the formula is to find "present" from future... we are finding future/present from past

OpenStudy (anonymous):

???

OpenStudy (anonymous):

ohh thats for him!!! What about mine!!! i sent a screen shot!! so its more clear!!

OpenStudy (anonymous):

@dmariscal you are in a test. and I have given enough information already, unknowlingly. this is against the code of conduct of the website and unethical. good luck.

OpenStudy (anonymous):

the time expired

OpenStudy (anonymous):

if you saw this was a screen shot form earlier today at noon

OpenStudy (anonymous):

i just wanted to see how to solve it, i already failed the test

OpenStudy (anonymous):

isee. :) ok

OpenStudy (anonymous):

@ dmariscal are you taking business calc? when do you have to get this prob done? Holy smokes I just read electrokid's response

OpenStudy (anonymous):

so, yes. what we did was right.

OpenStudy (anonymous):

how did we put it into terms of B(t) so t would be in our awnser?

OpenStudy (anonymous):

@TARAMAYO to be able to use the "@" tool correctly, you should not put a "space" after that "@" symbol.

OpenStudy (anonymous):

@electrokid so can you tell me what's my R(t) here? I've been waiting for hours, but if it's too late I'm going to the tutoring center tomorrow. Thanks.. CAPITAL VALUE: Suppose income from an investment starts (at time 0) at $6,000 a year & increases linearly & continuously at a rate of $200 a year. Find the Capital Value at an interest rate of 5% compounded continuously. Improper integral using R(t)e^(-rt)... Which amount is the R(t)? & what makes the other amount in this problem?

OpenStudy (anonymous):

@dmariscal then instead of b(0), put b(t) :) \[{\rm withdrawal:}\;B'(t)=0.05B(t)-11000\\ {\rm deposit:}\;B'(t)=0.05B(t)+11000 \]

OpenStudy (anonymous):

@TARAMAYO I am looking at it now..

OpenStudy (anonymous):

@electrokid you know what, nevermind, it's really late I've got to get up in 3hrs for work

OpenStudy (anonymous):

@TARAMAYO so, your rate is, +200 a year

OpenStudy (anonymous):

@electrokid Hey super thanks, I appreciate it! gnite!

OpenStudy (anonymous):

thanks so much

OpenStudy (anonymous):

one last question wouldnt it be .06t+11000

OpenStudy (anonymous):

then, its a linear increase.. so, \[ CV=\int I'(t)e^{-rt}dt=\int 6000e^{-0.05t}dt \]

OpenStudy (anonymous):

the intrest + the intial ? so why would B(t) be in there

OpenStudy (anonymous):

@dmariscal coz, you get some compound interest on whatever the balance you had at time t.. i.e., a lilttle compount intertest of 0.05B(t)

OpenStudy (anonymous):

okay cool!!

OpenStudy (anonymous):

Thanks again i wish i could pay you on this sight!!

OpenStudy (anonymous):

haha. np. ☮

OpenStudy (anonymous):

@dmariscal didn't see you on yesterday so here it is

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