Question

derivative of. . . .

Answer 1

\[f(x)=\cot \sqrt{x}\]

Answer 2

you can avoid remembering too many things and use chain rule
\[f(x)=\cot\sqrt{x}=(\tan\sqrt{x})^{-1}\\
f'(x)=(-1){1\over\tan^2\sqrt{x}}\times{d\over dx}(\tan\sqrt{x})\]

Answer 3

but if you do, remember the differential of "cot",
\[f'(x)=\csc^2\sqrt{x}\times{d\over dx}(\sqrt{x})\]

Answer 4

I forgot a negative sign in the second one..

Answer 5

thats ok. i know where thats suppose to be

Answer 6

both ways, you'd get the same answer.

Answer 7

so the answer i have is -csc^2 sqrt x /2 sqrt x

Answer 8

yep
thats the one