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Mathematics 9 Online
OpenStudy (anonymous):

is there a value of x where cos(x)=x

OpenStudy (anonymous):

Yeah, there is.

OpenStudy (anonymous):

Can you explain?

sam (.sam.):

Newton's method?

OpenStudy (anonymous):

You basically have to find the root of \[ \cos(x)-x=0 \]

OpenStudy (anonymous):

Think about it this way... As \(x\) goes from \(0\) to \(\pi\), \(\cos x\) goes from \(1\) to \(0\).

OpenStudy (anonymous):

And this happens in a one-to-one manner.

OpenStudy (anonymous):

Oh ok that makes sense. Thank you so much this really helps

OpenStudy (anonymous):

So they have to meet at some point.

OpenStudy (anonymous):

Should maybe say as \(x\) goes from \(0\) to \(\pi/2\)

OpenStudy (anonymous):

Although this wouldn't be very easy to solve algebraically, but one thing you know for sure is that this will have 1 solution since the line y = x and the curve y = cos(x) have to intersect at some point. @skater93

OpenStudy (anonymous):

It has 2 solutions, because the negative case is symmetrically identical.

OpenStudy (anonymous):

at least

OpenStudy (anonymous):

There is a single intersection point?

OpenStudy (amoodarya):

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