Question

find

Answer 1

\[y=\frac{x+1}{2x+1}\]
\[y(2x+1)=x+1\]
\[2xy+y=x+1\]
\[2xy-x=1-y\]
x(2y-1)=1-y
\[x=\frac{1-y}{2y-1}\]

Answer 2

oh
i was very close
@Mertsj thank u very much
now, x= g(y) =(1-y)/(2y-1)