Question

Identify the solutions of 3x^2-13x+4=0
A. x=-1/3, x=-4
B. x=1/3, x=4
C. x=-4/3, x=-1
D. x=4/3, x=1

Answer 1

y= ax^2 + bx +c
in your case a =3
b= -13
c = 4

Answer 2

do you know how to factor this equation?

Answer 3

I dont know how to do any of it ._. It's all friggin confusing as hell to me...

Answer 4

cool so we'll start there then: factors of "a"
what times what = 3?

Answer 5

1 times 3? lol

Answer 6

perfect!
so we'll have something that looks like :
( 3x + __ ) (1x + __ )

Answer 7

now, the factors of "c"
what times what = 4 (need both answers here)

Answer 8

1 times 4
2 times 2

Answer 9

easy as, we're breezin through

Answer 10

now to pick which one is ours, it has to add to equal "b" (-13)
also, as its a negative, both our factors are probably going to be negatives
so as "a" was 3 and 1:
3 times (4 or 1 or 2) + (4 or 1 or 2) = - 13

Answer 11

so pick your poison: -1,-4 or -2,-2
personally i'd go with the 3 times -4 (this equals -12) and -1 as this matches perfectly

Answer 12

so we've picked the factors that match this equation
so y = ax^2 + bx +c
y = 3x^2 -13x +4
y = (3x -1) (x - 4)
and as y = 0...

Answer 13

0 = (3x -1) (x - 4)
therefore what times what = 0?
answer: anything times 0 =0
so either 3x - 1 = 0 or x - 4 = 0
so either 3x = 1 or x = 4
so either x = 1/3 or x = 4

Answer 14

so one of those answers above matches up with those values of x

Answer 15

im lost ._. I still don't get it...

Answer 16

FML ill just guess. >.<

Answer 17

so either x = 1/3 or x = 4

Answer 18

both of these answers are correct, the graph of the line crosses the x axis at x=1/3 and again at x = 4, so your answer is b